My specific problem is: on a fixed (320*320) size image, there are 2 known object-detection boundingboxes, shown in green in the figure, The problem is that only the width and height (W and H) of another object-detection boundingbox(red color) are known, how to determine the x and y of the red object-detection boundingbox so that its intersection with all other green object-detection boundingboxes is 0 (All IOU=0)?
The object-detection boundingboxes is represented by four elements [x, y, w, h], respectively representing the x coordinate, y coordinate, rectangle width and height of the upper left corner of the image.
In the following example, the solution set of the coordinate range of the upper left corner of the red object-detection boundingbox should be {0<x<20,150<y<220}, but the program cannot solve it，and I tried to solve my problem in 2 ways, but I still can't get my answer. Why?
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我的具体问题是：在一副固定（320*320）大小尺寸的图像上，有2个已知的目标检测框，在图中用绿色显示，问题是仅已知另外一个检测框的宽和高（W和H)情况下,如何确定该红色检测框的x,y，使得其与其他所有绿色检测框的交并比都为0？
检测框用[x,y,w,h]四个元素表示，分别表示图像左上角x坐标，y坐标，矩形宽和高。
在以下示例中，红色检测框的左上角点坐标范围解集应该为 {0<x<20,150<y<220}，但程序无法解出，我尝试2种方法求解，但程序无法得到我的答案，请问为什么？
objectROIs = [50,50,100,100;
80,80,200,230];
image = zeros(320,320,3,'uint8');
image = insertObjectAnnotation(image,'rectangle',objectROIs,'object','Color','green');
imshow(image)
W = 60;
H = 100;
syms x y
eqn1 = x>0;
eqn2 = y>0;
eqn3 = x<320-W;
eqn4 = y<320-H;
eqn5 = sum(bboxOverlapRatio([x,y,W,H],objectROIs),'all')==0;
f = @(x,y)bboxOverlapRatio([x,y,W,H],objectROIs);
eqns = [eqn1,eqn2,eqn3,eqn4,eqn5];
S = solve(eqns,[x,y],'ReturnConditions',true)
W = 60;
H = 100;
fun = @(x)sum(bboxOverlapRatio([x(1),x(2),W,H],objectROIs),'all');
lb = [0,0];
ub = [320-W,320-H];
A = [];
b = [];
Aeq = [];
beq = [];
x0 = (lb + ub)/2;
options = optimoptions('fmincon','Display','iter','Algorithm','interior-point');
[x,fval,exitflag] = fmincon(fun,x0,A,b,Aeq,beq,lb,ub,@(x)mycon(x,W,H,objectROIs),options)
ious = bboxOverlapRatio([round(x),W,H],objectROIs)
image = insertObjectAnnotation(image,'rectangle',[round(x),W,H],'insert','Color','red');
imshow(image)
-----------------------------------------------------method1 error!-----------------------------------------------
Error using bboxOverlapRatio
The value of 'bboxA' is invalid. Expected input to be one of these types:
uint8, int8, uint16, int16, uint32, int32, single, double
Instead its type was sym.
Error in bboxOverlapRatio>validateAndParseInputs (line 195)
parser.parse(bboxA,bboxB,varargin{:});
Error in bboxOverlapRatio>iParseInputs (line 94)
[bboxA, bboxB, ratioType] = validateAndParseInputs(bboxA, bboxB, varargin{:});
Error in bboxOverlapRatio (line 55)
[bboxA, bboxB, ratioType, isUsingCodeGeneration] = iParseInputs(bboxA,bboxB,varargin{:});
Error in TEST (line 17)
eqn5 = sum(bboxOverlapRatio([x,y,W,H],objectROIs),'all')==0;
------------------------------------------------------------method2, No feasible solution! ？？？ ----------------------------------------------------------------------------------
Converged to an infeasible point.
fmincon stopped because the size of the current step is less than
the value of the step size tolerance but constraints are not
satisfied to within the value of the constraint tolerance.
<stopping criteria details>
x =
150.0000 110.3551
fval =
0.1304
exitflag =
-2
ious =
0 0.1304
function [c,ceq] = mycon(x,W,H,objROIs)
c = [];
ceq = sum(bboxOverlapRatio([round(x),W,H],objROIs),'all');
