Change uiAxes DateNum to DateTime in AppDesigner for animatedLine Plot

2020 6 3
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更新时间：2020 6 3
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Here, I have a UIAxes; with datenum tick marks. I have the values of x-ticks in String, as you can see from Time Field. I used datetickzoom and dynamicdateticks; but the zoom function gave error. Is there any possibility of changing these dateNum x-ticks to datetime ticks. It'll be better to use dynamic, but if there's no way for that, static vector ticks will also work.

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Cris LaPierre
Cris LaPierre 2020-6-3

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Can you convert your X data to datetime before plotting? Plots support datetimes as x values. You can convert a string to datetime using the datetime('06-Jun-2020 02:26:26') syntax.
You can use xtickformat function to format the datetime appearance.

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Umair Mughal
Umair Mughal 2020-6-3
编辑：Umair Mughal 2020-6-3
Yes, I can but the problem here is with animatedline (I'm not using plot function) that can't allow datetime values in argument.
% Draw Plot
try
if app.ShowAmpsCheckBox.Value == true
addpoints(h, datenum(x(k)), y(k, 1));
else
clearpoints(h);
end
if app.ShowUnitsCheckBox.Value == true
addpoints(j, datenum(x(k)), y(k, 2)); % I can't put datetime value in here
else
clearpoints(j);
end
catch
end
drawnow;
If I use this:
% Change X-Ticks to DateTime
%
% set(app.UIAxes, 'XTick', datenum(x(k)));
% datetick(app.UIAxes,'x','yyyy-mm-dd HH:MM:SS','keeplimits');
It gives a very bad looking plot.
Umair Mughal
Umair Mughal 2020-6-3
编辑：Umair Mughal 2020-6-3
See everything works perfectly after using plot... As I zoom; it even shows the time in seconds.
Cris LaPierre
Cris LaPierre 2020-6-3
编辑：Cris LaPierre 2020-6-3
If the appearance and labels are important, which I imagine they are, I would be inclined to suggest using plot instead of animatedline. Since I don't have your code, here's a simple example.
Somewhere, initialze the plot
l = plot(app.UIAxes,x(1),y(1,1))
Then, when you want to add points, update the XData and YData properties of your line object l.
l.XData = x(1:k);
l.YData = y(1:k,1);
And when you want to clear the points, you could do this.
l.XData = [];
l.YData = [];
I don't have your code, so you may need to do some slight modification to get this to work. If you are in app designer, you might also need to add l to your app properties, and reference it using app.l.

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