mean(x) function not actually taking the mean

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Joyce Ai 2020-6-3

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https://ww2.mathworks.cn/matlabcentral/answers/541700-mean-x-function-not-actually-taking-the-mean

关闭： MATLAB Answer Bot 2021-8-20

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So I have a code to find the average values (Avg.CAR.Block(i)) of EMG data across 22536 frames/data points. After I run the code, the mean should just give me one single number representing the average of all frames, but Avg.CAR.Block(i) still returns the exact same value as CAR.Block(i).

for i=1:3
    for j=1:length(Norm.Block(i).Rlong)
        %R:L Longissimus
        if Norm.Block(i).Rlong(j) <= Norm.Block(i).Llong(j)
            CAR.Block(i).RLlong(j)=Norm.Block(i).Rlong(j)/Norm.Block(i).Llong(j);
        else Norm.Block(i).Rlong(j)>Norm.Block(i).Llong(j);
            CAR.Block(i).RLlong(j)=Norm.Block(i).Llong(j)/Norm.Block(i).Rlong(j);
        end
%Average across block trials 
for i=1:3
    for j=1:length(Norm.Block(i).Rlong)
        AvgCAR.Block(i).RLlong(j)=mean(CAR.Block(i).RLlong(j));
        AvgCAR.Block(i).RLrectus(j)=mean(CAR.Block(i).RLrectus(j));
        AvgCAR.Block(i).RLrectus(j)=mean(CAR.Block(i).RLgmed(j));
        AvgCAR.Block(i).RLeo(j)=mean(CAR.Block(i).RLeo(j));
    end
end

These are the values of Avg.CAR.Block(i) and the CAR.Block(i) values are the exact same

Why isn't the mean function working?

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John D'Errico 2020-6-3

Is this:

CAR.Block(i).RLlong(j)

a scalar value? If so, then why do you expect mean to somehow remember the previous times it has been called? After all, if I compute mean(3), what value should it produce? If I then call mean(5), should mean do something other than return the value 5?

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