splitapply with @num2str
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I need to figure out how to set the precision of all numbers of a column in a table to 0.0 (i.e I have a value 34 that needs to output as 34.0). My professor has suggested using num2str is easier that sprintf for this matter. We have been learning about splitapply, so I thought maybe he intends for us to use that here. The table is from an excel file that I read in. Ergo, I have the following code:
table1 = table(Verb, meanEstimates);
meanEstimates = splitapply(@num2str, meanEstimates, '.1d');
I get the follow error message "Group numbers must be a vector of postitive integers, and cannot be a sparse vector."
In all honesty I don't really know what I'm doing because it's been hard to learn online this quarter.
2 个评论
madhan ravi
2020-6-3
It would be better if you share a short example values to experiment ;)
Kayla Black
2020-6-3
Ah okay, sorry, I never posted on here before so idk what I'm doing or maybe how to help you help me, but here's the table I'm working with. I just need to change 34 to 34.0 without hardcoding. Let me know if there's any more info you need from me.
采纳的回答
madhan ravi
2020-6-3
vpa(table1pretty{:,2},digits(5))
3 个评论
madhan ravi
2020-6-4
table1pretty.("mean speed estimate") = compose("%.1f", table1pretty.("mean speed estimate"))
Kayla Black
2020-6-4
madhan ravi
2020-6-4
I feel it too, been there done that. Best of luck!
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