Plot function with time step

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Niklas Kurz
Niklas Kurz 2020-6-4
编辑： Niklas Kurz 2020-6-5
Hello, even if this question was posed in a similar way, I couldn't apply it to my issue, also given the fact I'm very new.
However, I got a set of values (.txt format: A= 4063x1). Thus the y-values are provided, I'd name them y = A{:,1}; Unfortunaly x values are missing, it's just being said time step = 0.000999. That's what is bothering me: how am I generating my line of x-values? It'd be most kind if you'd solve that trivial thing for me. Thx in advance.

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采纳的回答

David Hill
David Hill 2020-6-4
I assume x is time then corresponding to your y-values with the given step starting at zero.
x=0:.000999:4.057938;
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Niklas Kurz
Niklas Kurz 2020-6-5
Thank you so much! (btw. for those who are facing the same problem: last number (4.057938) represents the product of 4062 times 0.000999 to match x and y values)

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更多回答（1 个）

Steven Lord
Steven Lord 2020-6-5
A slightly different way to create that vector would be to compute integer multiples of the spacing. First I'll make some sample Y data of the correct size:
y = rand(4063, 1);
Now build x.
timestep = 0.000999;
x = (0:numel(y)-1)*timestep;
  1 个评论
Niklas Kurz
Niklas Kurz 2020-6-5
编辑：Niklas Kurz 2020-6-5
Thank you for your answere as well. Maybe you happen to answere me an additional simple question: If I just want certain rows of my table to be chosen, how to achieve this? By typing y = A{:, 1}; Matlab picks all 4063 values. Pretending I just want to evaluate 2014-4063, what to do?

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