reduce vector each loop

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Ali Tawfik 2020-6-4

编辑： Ali Tawfik 2020-6-5

I am trying to reduce the vector length backward each loop, like the following: I think I should use for loop but i can not figure out how to do it

x=0:.1:1;

x=0 .1 .2 .3 .4 .5 .6 .7 .8 .9 1.0;

Then I would like the OUTPUT to be

x(1)= 0 .1 .2 .3 .4 .5 .6 .7 .8 .9

x(2)= 0 .1 .2 .3 .4 .5 .6 .7 .8

x(3)= 0 .1 .2 .3 .4 .5 .6 .7

.. ..

and so on.. until I reach to x(11)=0

madhan ravi 2020-6-4

The end indexing inside the loop would be total number of elements in x minus iterator.

madhan ravi 2020-6-4

x = 0:.5:1;
N = numel(x);
Wanted = cell(N,1);
for ii = 1:N
    Wanted{ii} = x(1: (N - ii)+1);
end
celldisp(Wanted)

Ali Tawfik 2020-6-5

编辑：Ali Tawfik 2020-6-5

x=0:0.1:1;
for i=1:length(x)
    x(1:(11-i)+1) % so the addition of one here to aviod make 1:0 
end 

thank you

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