Transfer function in Simulink different from Matlab
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Hey everybody,
I am plotting the step response of a transfer function with matlab and the result is fine.
Gs = (1/s^2) * (1 - 2*exp(-s*0.5) + exp(-s))
Now I am trying to build this function in Simulink with standard blocks, but the step response is different from matlab:
and
I have tried many different solver settings but the result is always the same. I anyone has Ideas what might be the problem, please let me know.
Thanks in advance,
Daniel.
4 个评论
Azzi Abdelmalek
2012-11-20
how did you get the first graph ( in matlab command)?
Daniel P
2012-11-21
Azzi Abdelmalek
2012-11-21
What version of matlab are you using? this did'nt work for me
Daniel P
2012-11-21
采纳的回答
Pedro Villena
2012-11-21
编辑：Pedro Villena
2012-11-21
0 个投票
Gs = (1/s^2) * (1 - 2*exp(-s*0.5) + exp(-s))
Gs = 1/s^2 - (2/s^2)*exp(-s*0.5) + (1/s^2)*exp(-s)
更多回答（1 个）
Ryan G
2012-11-20
0 个投票
The easiest way to achieve the desired results would be with the LTI System block which comes with the Control System Toolbox. This allows you to create a system in MATALB and directly utilize it in Simulink.
However, your model as shown works. You need to adjust the relative tolerance in the configuration parameters to be tighter. Try 1e-6 or 1e-8 and check the results.
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