Hi
I have data in 2D as a line data (example given as)
y1 x1 y2 x2 val err
36.97 126.5 36.79 126.45 394.94 1.79
36.98 126.4 36.79 126.45 179.59 0.75
37 126.65 36.55 126.64 82.64 0.35
37.4 127.21 37.35 126.7 379.76 1.53
34.75 127.17 34.4 126.7 172.95 0.73
37.45 126.82 37.89 126.77 401.29 1.6
36.98 126.4 37.08 126.77 1168.43 4.97
37.4 127.21 37.89 126.77 114.6 0.52
35.32 127.45 34.98 126.9 289.95 1.19
36.97 126.5 37.49 126.92 3462.07 15.01
37.16 127.52 37.49 126.92 151.54 0.61
37.4 127.21 37.49 126.92 167.04 0.69
37.16 127.52 37.49 126.92 240.72 1.01
36.2 127.48 36.27 126.92 235.94 0.95
36.35 127.2 36.27 126.92 155.95 0.63
35.27 127.42 35.49 126.93 1002.81 4.37
35.32 127.45 35.49 126.93 756.71 3.24
36.97 126.5 37.28 126.98 262.64 1.16
37.4 127.21 37.28 126.98 118 0.49
36.9 126.59 37.28 126.98 114.9 0.49
35.27 127.42 35.16 126.99 180.78 0.61
I need to interpolate the data. (The gridded data must be shown within the limits as defined by the user as Y (35.5 - 36.5) and X (128.5 - 129.5)
How I can do it. Waiting for your kind reply.

5 个评论

It is not possible to achieve what you want....the given points lie somewhere and the grid extents for which you want to interpolate are somehwere. Figure atatched.
Hi KSSV
Is it possible to make grid at that place according to data?
But what is the corresponding val for (x1,y1) and (x2,y2) data? Is val and err are same?
val is the corresponding value and err is the standard error
Dear KSSV
Thanks for your kind help.
I want to ask if we have only two lines as
140.5 35.25 140.75 35.5 10 1
140.25 35.5 140.5 35.75 5 2
What we have to change as when I run for only two lines the error message is
"Matrix dimensions must agree."
Thanks

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 采纳的回答

data = [36.97 126.5 36.79 126.45 394.94 1.79
36.98 126.4 36.79 126.45 179.59 0.75
37 126.65 36.55 126.64 82.64 0.35
37.4 127.21 37.35 126.7 379.76 1.53
34.75 127.17 34.4 126.7 172.95 0.73
37.45 126.82 37.89 126.77 401.29 1.6
36.98 126.4 37.08 126.77 1168.43 4.97
37.4 127.21 37.89 126.77 114.6 0.52
35.32 127.45 34.98 126.9 289.95 1.19
36.97 126.5 37.49 126.92 3462.07 15.01
37.16 127.52 37.49 126.92 151.54 0.61
37.4 127.21 37.49 126.92 167.04 0.69
37.16 127.52 37.49 126.92 240.72 1.01
36.2 127.48 36.27 126.92 235.94 0.95
36.35 127.2 36.27 126.92 155.95 0.63
35.27 127.42 35.49 126.93 1002.81 4.37
35.32 127.45 35.49 126.93 756.71 3.24
36.97 126.5 37.28 126.98 262.64 1.16
37.4 127.21 37.28 126.98 118 0.49
36.9 126.59 37.28 126.98 114.9 0.49
35.27 127.42 35.16 126.99 180.78 0.61 ] ;
y1 = data(:,1) ; y2 = data(:,3) ;
x1 = data(:,2) ; x2 = data(:,4) ;
val = data(:,5) ; err = data(:,6) ;
m = 100 ;
xi = linspace(min(x1),max(x1),m) ;
yi = linspace(min(y1),max(y1),m) ;
[X,Y] = meshgrid(xi,yi) ;
V = griddata(x1,y1,val,X,Y) ;
pcolor(X,Y,V)
shading interp

1 个评论

Dear KSSV
I need your more help
for the same data, I need node values if possible.
Waiting here for your kind reply.

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