Scaling the values to specific range

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Q=[ 0.0669
0.0383
0.0029
-0.0344
-0.0554
-0.0459
-0.0316
0.0086
0.0392
0.0650
0.0698
0.0478
0.0201
-0.0134
-0.0468
-0.0583
-0.0468
-0.0229
0.0115]
I want to scale the value of Q in range [-(2^13-1),(2^13-1)]
please help
  6 个评论
Walter Roberson
Walter Roberson 2012-11-21
I can't be bothered to research dwt2() to find out what the possible theoretical output ranges are for each possible class of input data. How about if you just state the value ranges and any specific encoding instructions ?
Pat
Pat 2012-11-21
walter these are coefficients from dwt2
S=[ 0.0038
0.0019
0.0105
0.0048
0.0038
-0.0105
-0.0134
-0.0191
-0.0258
-0.0229
-0.0086
-0.0076
-0.0086
-0.0010
0.0038
0.0048
0.0019
-0.0038
-0.0086
-0.0029
0.0038
0.0086
0.0096
0.0124
0.0057
0.0067
-0.0010
0.0029
0.0086
0.0057]
from this i have to sample in that range i.e in 14 bit range .
for 16 bit i have performed
D1=int16(S*32768);please tell how to perform for 14 bit

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采纳的回答

Harshit
Harshit 2012-11-21
D1=int16(S*32768) maps your any integer S*32768 outside the range to 32768 or for S>1 the output will be 32768(2^15) otherwise it will be round off to the nearest integer(You are assuming maximum non saturating input is 1 beyond this there will be saturation). You can see simply use max(round(2^13*S),2^13). Hope it will be fine.
  13 个评论
Pat
Pat 2012-11-21
ok thanks a lot harshit my final question,i have performed operation on cA,if i am usind idwt2,have i to perform same operation for ch,cV,cD for effictive reconstruction,else performing on cA is enough
Harshit
Harshit 2012-11-26
I will say you to do it because fixed point operations are done similarly.

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更多回答(1 个)

Walter Roberson
Walter Roberson 2012-11-21
Qscaled = 2^13-1;
(Your permitted range consists of exactly one value, so all numbers must scale to that one value.)
  2 个评论
Pat
Pat 2012-11-21
sorry walter it is
[-(2^13-1),(2^13-1)]% a signed 14 bit
Jan
Jan 2012-11-21
编辑:Jan 2012-11-21
@Pat: Instead of adding comments, fixing this error by editing the question would be less confusing for the readers. So please fix this.

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