why this code not displaying else part
显示 更早的评论
the following code is only displaying the if part even if the value is less than 0.6
y = sprintf('%.1f',rand(1))
if y>0.6
disp('the value is false')
else
disp('true')
end
采纳的回答
madhan ravi
2020-6-7
0 个投票
Remove sprintf()
13 个评论
madhan ravi
2020-6-7
And in fact your if else can be replace with
Condition = y > .6 % 1 means true and 0 means false
abdul rehman
2020-6-7
madhan ravi
2020-6-7
Huh? More illustrations needed with an example. Because the comment is totally vague.
abdul rehman
2020-6-7
madhan ravi
2020-6-7
doc round
abdul rehman
2020-6-7
madhan ravi
2020-6-7
编辑：madhan ravi
2020-6-7
Read the input arguments of that function in documentation ;).
>> round(.3555,1)
ans =
0.4000
>>
abdul rehman
2020-6-7
madhan ravi
2020-6-7
A totally vague comment not useful to understand at all.
madhan ravi
2020-6-7
编辑：madhan ravi
2020-6-7
”madhan ravi your answars are incomplete“
Yes because it’s your homework and not mine. Don’t expect others to do your homework. Make sure to READ the documentations properly before bashing others!
”you must know round only take single argument. Sorry but you are wasting time and your as well“
Not sure who’s wasting whose time here.Did you even read the documentation ?
Steven Lord
2020-6-7
As of release R2014b the round function has a syntax that accepts multiple inputs. abdul rehman, are you using a release prior to release R2014b? If so that would explain why madhan ravi's suggestion didn't work for you.
madhan ravi
2020-6-7
Thanks Steven.
abdul rehman
2020-6-7
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