inputing pi in syms

Hello,
I am working with the code bellow & R2020a.
The answer provided is:
result:
which is correct.
However, I would much prefare the answer to be given in the form:
aim:
Is there a way to do so?
So far I tried using
pi = sym('pi')
and
pi = sym(pi)
or just pi as a symbol.
In the best senario I get the number answer (389.6364); in the worst I obtain this:
Thank you,
The code used:
syms k x L E I
pi = sym(pi)
% Trial function
w = k * (1- cos(2*pi*x/L))
% Derivatives
w_x = diff(w,x,1)
w_xx = diff(w,x,2)
% x_y = diff(w,y,1)
% x_yy = diff(w,y,2)
% Strain
U = 1/2* int((E*I*w_xx^2),[0,L])

5 个评论

Why do you expect the sun part to disappear?
Yes but once you define pi using syms it doesn’t revalues the expression.
indeed that is the basis of my question.
Is there a way to obtain:
  • a final answer with π
  • and where π is 'understood' as 3.14... so eg. ends up being zero
Basically, can I obtain this:
I have checked with R2020a and the code that you have mentioned is working fine for me with sin(4pi) turning to zero.

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