Calculating double integral for exponential function

Hi everyone! I'm trying to calculate this integral using Matlab but, being a beginner, I'm struggling a bit.
This is the code I attempted using the documentation, but by some reason the answer isn't correct. Any help improving it will be appreciated.
fun = (@(x,y) exp(x.^2));
xmin = @(y) y;
q = integral2(fun, 0, 1, xmin, 1);

2 个评论

Could you explain why the result is wrong?
If calculated manually, the result of the integral gives 0.85914
However, when run through MATLAB, its 0.6035

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 采纳的回答

syms x y
fun = exp(x.^2)
Wanted = vpa(int(int(fun,x,y,1),y,0,1))
% however I’m not sure why it returns that result

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