AWGN function snr parameter

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Marcin Kolacz
Marcin Kolacz 2020-6-7
编辑： Marcin Kolacz 2021-1-17
Hi,
could someone explain to me please, why increasing the value of 'snr' parameter of awgn() function results in the outcoming signal being closer to the original (less interrupted). As far as I know, the bigger the SNR, the more interrupted the signal should be.
If the noise is 20dB, the resulting signal should be worse than in case of 10dB noise, isn't it?
Could someone explain why does it work this way?
edit: yeah im stupid

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回答（1 个）

Asvin Kumar
Asvin Kumar 2020-6-10
A higher Signal to Noise Ratio (SNR) would mean that the Signal Power is more as compared to the Noise Power. When that is the case, the output signal from AWGN will be closer in resemblance to the original signal.

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