Specialized sorting of array while preserving order

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how can i sort an array (of even number of elements) so the elements on the left side are smaller than the elements on the right side but without changing the original order of the elements in the array?
for example:
a = [19 21 12 -15 18 1 22 11];
r = [12 -15 1 11 19 21 18 22];
12 is prior to -15 in the original array and so it is in the result.
another example:
a = [8 4 2 6 3 1 9 10];
r = [ 4 2 3 1 8 6 9 10];
  1 个评论
Thomas
Thomas 2012-11-21
编辑:Thomas 2012-11-21
Why is 12 first. The results seems to be random.
but 4 is larger than 2..

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Matt Fig
Matt Fig 2012-11-21
编辑:Matt Fig 2012-11-21
% Your original array
a = [19 21 12 -15 18 1 22 11];
% Now the method:
L = length(a)/2;
[~,J] = sort(a); % For older MATLAB vers,[J,J] = sort(a);
[~,J] = sort(J);
r = [a(J<=L) a(J>L)]
  4 个评论
Zaza
Zaza 2012-11-21
i read the help of sort but i still don't feel comfortable with that...
can you give me please a simple step-by-step ex.? it would be very helpful for me...
Matt Fig
Matt Fig 2012-11-21
编辑:Matt Fig 2012-11-21
Zaza, it seems you already have a step-by-step example! Perhaps this will help. Here is another (preferable) way of solving the problem:
L = length(a)/2;
[~,J] = sort(a);
J(J) = 1:L*2;
r = [a(J<=L) a(J>L)]
Now have a look at Loren's blog entry on this method:

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