storing values in a loop
1 次查看(过去 30 天)
显示 更早的评论
I have a function of the following and it only gives the last value. I want to see a vector of Nf and pf. I tried inserting i. For example Nf(i)=Nf and received the following error:
Attempted to access Nf(2); index out of bounds because numel(Nf)=1.
Error in probabilitycounter (line 23) Nf(i)=Nf
Here is what I have written to produce actual data:
function [Nf,pf]= probabilitycounter(N,mu_x,mu_y,sig_x,sig_y)
%Starting value of Nf
Nf=0;
%Creating a loop to generate pf and Nf
for i=1:N
%Random variable declaration for ux and uy
u_x=rand(1,1);
u_y=rand(1,1);
%Normal Inverse
x=norminv(u_x,mu_x,sig_x)
y=norminv(u_y,mu_y,sig_y)
%Starting Nf and pf Calculation
if (x-y>0)
Nf=Nf+1;
else
Nf=Nf;
end
pf=Nf/N;
end
3 个评论
John Petersen
2012-11-21
These lines look like problematic
Nf(i) = Nf+1;
Nf(i) = Nf;
Maybe you want to index the Nf on both sides?
采纳的回答
Matt J
2012-11-21
I'm guessing this might be what you want:
function [Nf,pf]= probabilitycounter(N,mu_x,mu_y,sig_x,sig_y)
%Starting value of Nf
Nf=zeros(1,N);
%Creating a loop to generate pf and Nf
for i=2:N
%Random variable declaration for ux and uy
u_x=rand(1,1);
u_y=rand(1,1);
%Normal Inverse
x=norminv(u_x,mu_x,sig_x)
y=norminv(u_y,mu_y,sig_y)
%Starting Nf and pf Calculation
if (x-y<0)
Nf(i)=Nf(i-1)+1;
else
Nf(i)=Nf(i-1);
end
pf(i)=Nf(i)/N;
end
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!