why there is only one value at my plot

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Hakan Güngör
Hakan Güngör 2020-6-9
评论： darova 2020-6-12
syms t
t = 0:0.1:15;
a = ((30-30.*exp(-2.*t)).*(30.*t+15.*exp(-2.*t)+35))/(sqrt(490000-(30.*t+15.*exp(-2.*t)+35).^2));
plot(t,a)
here is my code. it just calculate a for t=15 and just show it on plot. i am new in matlab. could you help me?

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回答（1 个）

Tommy
Tommy 2020-6-9
Without the below period, MATLAB is performing right matrix division on two 1x151 vectors, resulting in a scalar value.
t = 0:0.1:15;
a = ((30-30.*exp(-2.*t)).*(30.*t+15.*exp(-2.*t)+35))./(sqrt(490000-(30.*t+15.*exp(-2.*t)+35).^2));
% ^ period added here
plot(t,a)

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