help to input sqrt function

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marwan alamah
marwan alamah 2020-6-10
评论： Walter Roberson 2020-6-12
z=sqrt(sin(x.^2+y.^2))\sqrt(x.^2+y.^2)
is this code input correct for this function
z=(sin√(x^2+y^2 ))/√(x^2+y^2 )

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回答（2 个）

Walter Roberson
Walter Roberson 2020-6-10
编辑：Walter Roberson 2020-6-12
z = sqrt(sin(x.^2+y.^2)) ./ sqrt(x.^2+y.^2);
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marwan alamah
marwan alamah 2020-6-10
it did not work
tell me it is undefined function or variable x
what should i do
Walter Roberson
Walter Roberson 2020-6-12
It is not clear why you would want to compute z=sqrt(sin(x.^2+y.^2))\sqrt(x.^2+y.^2) if x and y are not defined?
Perhaps you are wanting to create a function. If so then Rohith Nomula's "myfun" would work.

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Rohith Nomula
Rohith Nomula 2020-6-10
For this
z=(sin√(x^2+y^2 ))/√(x^2+y^2 )
For x and y as single elements
z=sin(sqrt(1^2+2^2))
z=z/(sqrt(1^2+2^2))
For a function
function z = myfuc(x,y)
z= sin(sqrt(x^2+y^2))/sqrt(x^2+y^2);
end
Try declaring it this way
  1 个评论
Walter Roberson
Walter Roberson 2020-6-12
The code to be implemented involves the dot versions of the operators, so the function should as well:
function z = myfuc(x,y)
z= sin(sqrt(x.^2+y.^2)) ./ sqrt(x.^2+y.^2);
end

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