help to input sqrt function
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z=sqrt(sin(x.^2+y.^2))\sqrt(x.^2+y.^2)
is this code input correct for this function
z=(sin√(x^2+y^2 ))/√(x^2+y^2 )
回答（2 个）
Walter Roberson
2020-6-10
编辑：Walter Roberson
2020-6-12
z = sqrt(sin(x.^2+y.^2)) ./ sqrt(x.^2+y.^2);
3 个评论
Walter Roberson
2020-6-10
z = sqrt(sinc(x.^2 + y.^2))
marwan alamah
2020-6-10
Walter Roberson
2020-6-12
It is not clear why you would want to compute z=sqrt(sin(x.^2+y.^2))\sqrt(x.^2+y.^2) if x and y are not defined?
Perhaps you are wanting to create a function. If so then Rohith Nomula's "myfun" would work.
Rohith Nomula
2020-6-10
For this
z=(sin√(x^2+y^2 ))/√(x^2+y^2 )
For x and y as single elements
z=sin(sqrt(1^2+2^2))
z=z/(sqrt(1^2+2^2))
For a function
function z = myfuc(x,y)
z= sin(sqrt(x^2+y^2))/sqrt(x^2+y^2);
end
Try declaring it this way
1 个评论
Walter Roberson
2020-6-12
The code to be implemented involves the dot versions of the operators, so the function should as well:
function z = myfuc(x,y)
z= sin(sqrt(x.^2+y.^2)) ./ sqrt(x.^2+y.^2);
end
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