find average in for loop

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Travis nguyen 2020-6-10

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https://ww2.mathworks.cn/matlabcentral/answers/546020-find-average-in-for-loop

编辑： John McDowell 2020-6-11

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Please help me , i want to find average y of each incease unit pr.

for example . at pr =0 . y1 = a b c

at pr = 0.5 , y 2 = a1 b1 c1

at pr = 1 , y3 = a2 b2 c2

at pr = 1.5, y4 = a3 b3 c3

at pr = 2 , y 5 = a4 b4 c4

find average of y yavg = avg(A) Avg(B) Avg(C )

note A is sum of a , a1, a2, a3, a4,

how i can code that.

a = 2;
b = 0;
n =2 ;
pr =[b:1:a];
 Pr =zeros(1,length(pr));
 heght = zeros(1,3);
 x = zeros(1,3);
 y = zeros(1,3);
 r = zeros (1,n);
 c = zeros(11,3)
total = zeros(1,3);
rec = zeros(3,3)
 for t=1:length(pr)
     rec = pr(t);
     Pr(t) = rec; 
      for i = 1:3
          Dis = 100 /7 * (i-1);
 
          heght = 10 - Pr(t);
          x(i) = Dis;
  
          for a = 1: n
            r(a) = sqrt((20 - Pr(t)) ^ 2 + x(i) ^ 2);
          end 
      y(i) = 100* sum(r);
     
      end   
 end 

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KSSV 2020-6-10

Not clear.

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Answer 1

John McDowell 2020-6-10

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/546020-find-average-in-for-loop#answer_449339

编辑：John McDowell 2020-6-11

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Hi Travis,

If I'm interpretting your question correctly, I think you want to make a list of average values within each time step of your loop (assuming t is time). You're really close:

for t = 1:Arbitrary
    y(t,:) = [a(t), b(t), c(t)];
end
yavg = [mean(y(:,1), mean(y(:,2), mean(y(:,3)]; % Or whatever average you choose.

I also notice that in your description, you want your time step to go up by 0.5. In order to do that, you need to ammend your pr definition to:

pr =[b:0.5:a];

I hope this helps.

Cheers,

John

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Travis nguyen 2020-6-10

Thanks John,

i have a question . for the y1(t,:) = [a(t), b(t), c(t)]; do i have to do for y2(t,:) and y3(t,:)

John McDowell 2020-6-11

在 MATLAB Online 中打开

Hi Travis,

I'm afraid that depends on your application! I interpretted your y1, y2, y3 notication as being at time steps 1,2,3 of your loop:

y(1,:) = [a(1), b(1), c(1)];
% Then as your time step increases to 2...
y(2,:) = [a(2), b(2), c(2)];

If this is not the case, can I ask you to try rephrasing your question? There's a lot of ambiguity in there. I'm sure it's obvious to you, but for us seeing it on this end, there's a lot of ways your question could be interpretted.

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