0 个投票

hi,
how to pre-allocate this:
for ii = 1:numel(L);
for jj=1:numel(L);
for kk=1:45;
c=cross(L1(ii,:),a{jj}(kk,:));
end
end
end

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Stephen23
Stephen23 2020-6-11

0 个投票

n = numel(L);
c = cell(n,n,45);
for ii = 1:n
for jj = 1:n
for kk = 1:45
c{ii,jj,kk} = cross(L1(ii,:),a{jj}(kk,:));
end
end
end

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