How can I found character in a 2D array
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I have a problem about create a function which is tried to do at each row of a 2D character array there is a string which can have duplicate characters.I had tried to create function called "is_existing" that will accept two inputs one of the inputs arrays An array (say X) with above-given properties, and another 2D character array (say Y) whose number of columns is equal to the number of columns of X. The number of rows of these two arrays can be different. The output will be a column vector whose number of rows is equal to the number of rows of Y. For any row of Y, if there exists a row of X that is composed of a permutation of the string given in this row of Y, the corresponding element of the output vector will be logical 1. Otherwise, it will be logical 0.
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I tried this
X=['133ABC36';'V2EL8A3V';'9MEHHET9';'919EY9EN'];
Y=['C3C3C3C3';'631A3B3C';'ETM99MEH'];
rowY=size(Y)(1);
colY=size(Y)(2);
rowX=size(X)(1);
colX=size(X)(2);
test=zeros(rowX,colX);
for i=1:rowY
for j=1:colY
for k=1:rowX
for t=1:colX
if Y(i,j)==X(k,t)
test(k,t)=1;
end
end
end
end
end
I couldn't create a function.It doesn't works like what I want.
5 个评论
KSSV
2020-6-12
Read about strcmp, strfind.
Hazar Can Dai
2020-6-12
Anna Case
2020-6-12
If you want case-insensitvity, use strcmpi()
Hazar Can Dai
2020-6-12
采纳的回答
The simplest way I can think to code would be
is_existing=ismember(sort(Y,2),sort(X,2),'rows');
or
is_existing=contains(string(sort(Y,2)),string(sort(X,2)));
It takes a looping over the two arrays in double loop to use ismember directly on the char() arrays to avoid the cross-comparison over the whole arrays that returns T for all strings in Y being in X as the characters do exist in the array somewhere. The sort puts in order so then a direct match is what are looking for, by the 'rows' option.
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