This simple code note working, HELP
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%this works well upto t==0.7, but not after 0.8
%give me an answer for this, not links
t=0;
for n=1:10
t=t+0.1;
disp(t)
if t==0.8
disp('if')
else
disp('else')
end
end
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Ameer Hamza
2020-6-13
编辑:Ameer Hamza
2020-6-13
Direct comparison using == of floating-point number does not give the correct result. You need to allow some level of tolerance. Try this
t=0;
for n=1:10
t=t+0.1;
disp(t);
if abs(t-0.8) < 1e-6
disp('if')
else
disp('else')
end
end
3 个评论
Ameer Hamza
2020-6-13
yes, that will work as well, but it is good to use the tolerance method. Otherwise, you will need to do rounding every time you do some mathematical operation on the variable.
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