Convolution giving decimal point in the result

Question

Zamani Md Sani 2020-6-13

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/547554-convolution-giving-decimal-point-in-the-result

评论： Ameer Hamza 2020-6-13

Hi,

Im trying to learn to look on the result from the kernel after convolution. Even i followed youtube for the double on the data but yet has a problem with the result.

Here is the code and the result, i don't know what else i had to change..

I = imread('C:\\MEKH\\LENA.jpg');
figure, imshow(I);
J=rgb2gray(I);
figure, imshow(J)
J=double(J)
A = [1,1,1;1,1,1;1,1,1]/9;
B = conv2(J,A,'same')
B=double(B)
figure, imshow(B)
Result:
Input
J =
   222   208   255   255   253
   105   141    82   108   169
   121   252     4     1   124
    89   124    79   195   227
   253   252   196   221   250
B =
   75.1111  112.5556  116.5556  124.6667   87.2222
  116.5556  154.4444  145.1111  139.0000  101.1111
   92.4444  110.7778  109.5556  109.8889   91.5556
  121.2222  152.2222  147.1111  144.1111  113.1111
   79.7778  110.3333  118.5556  129.7778   99.2222

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Answer 1

Ameer Hamza 2020-6-13

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/547554-convolution-giving-decimal-point-in-the-result#answer_450642

编辑：Ameer Hamza 2020-6-13

在 MATLAB Online 中打开

the output of conv2() is expected to be a fractional number. To use imshow, first convert it to uint8(). There are two alternatives

Convert the output of conv to uint8

I = imread('C:\\MEKH\\LENA.jpg');
figure, imshow(I);
J = rgb2gray(I);
figure, imshow(J)
J = double(J)
A = [1,1,1;1,1,1;1,1,1]/9;
B = conv2(J,A,'same')
B = uint8(B)
figure, imshow(B)

Or, use im2double() to convert the original image to double datatype

I = im2double(imread('C:\\MEKH\\LENA.jpg'));
figure, imshow(I);
J=rgb2gray(I);
figure, imshow(J)
A = [1,1,1;1,1,1;1,1,1]/9;
B = conv2(J,A,'same')
figure, imshow(B)