Value Exceeds while dividing
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I have 2 matrices
A ranges between -32768 to 32767 ,it is 100x1 matrix
class(A) is int16
B matrix ranges from -1473 to 1570,it is 100x1 matrix
class(B) is double
asuming i divide manually the values ,max(B)/max(A), i get correct answer , but while runnning in m file , the value exceeds
The maximum value must be .049 ,but i get 1.73,
I converted both A and B to double,still i get same error ,
please assist
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Walter Roberson
2012-11-26
What happens if you break it up and display the values:
ma = max(A)
class(ma)
size(ma)
mb = max(B)
class(mb)
size(mb)
mb / ma
mb ./ ma
9 个评论
Pat
2012-11-26
Walter Roberson
2012-11-26
So the problem has gone away?
Pat
2012-11-26
Walter Roberson
2012-11-26
编辑：Walter Roberson
2012-11-26
What happens if you paste the commands into the .m file right after your current calculation ?
ma = max(A)
class(ma)
size(ma)
mb = max(B)
class(mb)
size(mb)
double(mb) ./ double(ma)
and what is the exact line you are using for calculation at the moment?
Pat
2012-11-26
Walter Roberson
2012-11-26
编辑：Walter Roberson
2012-11-26
I don't know: you do not show the other values you are dividing.
If you are dividing elements of A and B pairwise, then the maximum possible result is reached if max(B(B>0)) is at the same location as min(A(A>=0)), or if min(B(B<0)) is at the same location as min(A(A<0)); and the maximum can be infinite because 0 is a valid member of A; NaN is also a possible output if a 0 in B happens to be at the same location as a 0 in A.
Pat
2012-11-26
Walter Roberson
2012-11-26
Any non-zero value divided by 0 gives an infinite result, which is going to be more than 5 bits.
If you have a 14 bit value divided by 1 (which is a valid 16 bit value) then you are going to get a 14 bit value output.
Any 14 bit value divided by a value that could be represented (without compression) in 8 or fewer binary digits, is going to give a result that requires more than 5 bits.
64 (7 bits) / 2 (2 bits) = 32 (6 bits) so the numbers represented as 14 bits can be pretty small and you would still have problems.
Pat
2012-11-26
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