Set logical array values to true if value n values ahead is true
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I'm curious if anyone can find a smart/clean way (other than a for loop of doing the following). Given a logical array x:
x = logical( [0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0] );
For n = 1 I'd like: y = [0, 0, 0, 1, 1, 0, 0, 0, 1, 1, 0, 0];
For n = 2 I'd like: y = [0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0, 0];
etc.
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Your examples conflict with your description. Do you want to place n values in the array ahead of a 1 as your examples show, or do you want to place a single 1 ahead of n 1s, as the title implies? If the latter, do you need to place a 1 only in front of exactly n 1s, or at least n 1s?
Chris
2012-11-27
采纳的回答
Andrei Bobrov
2012-11-26
x = [0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0] > 0;
n = 2;
x(bsxfun(@minus,find(x),(n:-1:1)')) = true;
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