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Variable Substitution Using Symbolic Functions

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Angel Quintanilla
Angel Quintanilla 2020-6-17
评论： madhan ravi 2020-6-17
syms A(t) B(t) C(t) t
syms X Y Z
D=A+B+C
D(t) =
Ds=subs(D,[A,B,C],[X,Y,Z])
Ds(t) =
I'm trying to substitute a time function for dummy variables that aren't interpreted as functions of time. Here I would assume X,Y,Z would not be functions of t since X,Y,Z aren't declared as such.
My goal is to treat both x(->a) and dx/dt(->b) as two separete variables that I can differentiate to get dx/dt and dx^2/dt^2(->c)
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Angel Quintanilla
Angel Quintanilla 2020-6-17
the equations are pretty long but for example:
Ds=X+Y+Z where XYZ represent dummy variables and not not functions of time.
Hence Ds is not Ds(t) a funtion of time but of XYZ which are variables and not functions
madhan ravi
madhan ravi 2020-6-17
See my answer below ;) then if you don’t want the equation to be a function of time.

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采纳的回答

madhan ravi
madhan ravi 2020-6-17
Use formula()

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