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Increase counter for each element in array

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Dario Walter
Dario Walter 2020-6-17
评论： Dario Walter 2020-6-18
Hey,
given A = [1 1 3 4 5 6 6 7 7 7]. How could I return the sequence B =[1 2 1 1 1 1 2 1 2 3] such that each duplicate is counted and B is the same size as A?
I appreciate your help!

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采纳的回答

madhan ravi
madhan ravi 2020-6-17
ix = A(:) == unique(A);
B = nonzeros(cumsum(ix) .* ix)
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madhan ravi
madhan ravi 2020-6-18
I knew you would come up with that question. That’s why you should experiment with 'stable' option in unique function.

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