Increase counter for each element in array
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Hey,
given A = [1 1 3 4 5 6 6 7 7 7]. How could I return the sequence B =[1 2 1 1 1 1 2 1 2 3] such that each duplicate is counted and B is the same size as A?
I appreciate your help!
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madhan ravi
2020-6-17
ix = A(:) == unique(A);
B = nonzeros(cumsum(ix) .* ix)
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madhan ravi
2020-6-18
I knew you would come up with that question. That’s why you should experiment with 'stable' option in unique function.
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