Finding the solution of a system of equations

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Steewz
Steewz 2020-6-18
评论： Kshitij Chhabra 2020-6-22
Hey i would like to find the solutions for this system assuming that my unknows are X Y and Z
solve doesnt work
syms X Y Z
eq1=sqrt((a1-X)^2+(b1-Y)^2+(c1-Z)^2) == D1+R1;
eq2=sqrt((a2-X)^2+(b2-Y)^2+(c2-Z)^2) == D2+R2;
eq3=sqrt((a3-X)^2+(b3-Y)^2+(c3-Z)^2) == D3+R3;
eq4=sqrt((a4-X)^2+(b4-Y)^2+(c4-Z)^2) == D4+R4;
TY

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回答（1 个）

Kshitij Chhabra
Kshitij Chhabra 2020-6-18
Hi Steewz,
From the question, I understand that you want to solve the given set of quadratic equations for X,Y,Z. Since not specified in the question, I am assuming the other variables as constants which can be specified later(or you can assign them to be syms variable too).
For the above problem you may try using solve function in the following way:
sol = solve([eq1, eq2, eq3], [X, Y, Z]);
For accessing the results you may use:
sol.X;
sol.Y;
sol.Z;
  2 个评论
Steewz
Steewz 2020-6-18
Hi,
Thank you for your answer, yes you are right the other variables are constants which are determined earlier in my code, i've already tried the solution you proposed and it works, but it's only with 3 equations, I want to solve the system with 4 equations, and this is the problem xD
Kshitij Chhabra
Kshitij Chhabra 2020-6-22
Hi,
Writing the above code as:
sol = solve([eq1, eq2, eq3,eq4], [X, Y, Z]);
should solve the problem too, If it's giving some unexpected behavior it'd be helpful if you could share the values of constant as well.

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