what is wrong in this code in matlab?
显示 更早的评论
hi can you tell me what is wrong in this code becouse o got wrong message which is (??? Undefined function or method 'sqr' for input arguments of type 'double')
for (c1=sqr(features1(:,j)- mean_of_column1); and
p1=0;
p2=0;
for j=1:c
c1=sqr(features1(:,j)- mean_of_column1);
c2=sqr(features2(:,j)- mean_of_column2);
p1=p1+c1;
p2=p2+c2;
end;
denominator=sqrt(p1)* sqrt(p2);
1 个评论
Walter Roberson
2011-4-14
'and' is not valid at that position in the code.
采纳的回答
Matt Fig
2011-4-14
You probably mean to use the SQRT function to find the square root.
In response to your clarifying comment,
sqr = @(x) x.^2; % Define this first, before you use it!
sqr(5)
7 个评论
Matt Fig
2011-4-14
Another example of the poor search capabilities on TMW website. Searching for sqrt in "latest documentation" doesn't turn up the non-symbolic form of this function in the first three pages!
Taleb Almajrbi
2011-4-14
Matt Fig
2011-4-14
In that case:
sqr = @(x) x.^2; % Define this first.
sqr(5)
Taleb Almajrbi
2011-4-14
Matt Fig
2011-4-14
Just like I showed you! First define the function, then use the function. Put the function definition line
sqr = @(x) x.^2; % Define this first.
anywhere in the code BEFORE you use it.
Taleb Almajrbi
2011-4-14
Matt Fig
2011-4-14
Yes, whenever you are working with arrays and need to do element by element multiplication, use this instead:
sqrt(p1).* sqrt(p2); % Notice the .* instead of * only.
The same goes for / and ^.
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Logical 的更多信息
2011-4-14
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
