Discrete system solving with MATLAB
显示 更早的评论
Hello ! question : y[n]+1/4*y[n-1]-1/8y[n-2]=x[n] this discrete system , how do i solve it with matlab ? must i do z transform ? what is z transform code ? we will do h(z)=y(z)/x(z) and we find roots..??
1 个评论
Mansoor Khalid
2019-5-25
Consider an input of a signal given as x(n)={1,2,3} and the impulse response of a system given as h(n)={4,5,6} for 0< equal n < equal 3 find and sketch the output y(n).
采纳的回答
Azzi Abdelmalek
2012-11-29
编辑：Azzi Abdelmalek
2012-11-29
you will need initials condition y(0) and y(-1); because Matlab don't allow negative index we 'll consider y(2) and y(1) as initials conditions
y(1)=0;
y(2)=0
k=0:20;
x=exp(-2*k); %your input system;
for n=3:numel(k)
y(n)=-(1/4)*y(n-1)+(1/8)*y(n-2)+x(n-2)
end
hold on
stem(k(1:end-2),y(3:end),'r');
Or you can use lsim command
N=[1 0 0];D=[1 1/4 -1/8];
te=1 % Sample time
model=tf(N,D,te);
lsim(model,x,k,[0 0])
3 个评论
Ismail
2012-11-29
Azzi Abdelmalek
2012-11-29
编辑：Azzi Abdelmalek
2012-11-29
You are looking for impulse response which means that the input is the Kronecker delta x=[1 0 0 0 0 0 ...]
you can also use the impulse function
N=[1 0 0];D=[1 1/4 -1/8];
te=1 % Sample time
model=tf(N,D,te);
impulse(model)
Azzi Abdelmalek
2012-11-29
编辑：Azzi Abdelmalek
2012-11-29
Ah I did'nt well read your comment. I also did'nt understand your question, you transfer function H(z) is already given by model
N=[1 0 0];D=[1 1/4 -1/8];
te=1 % Sample time
model=tf(N,D,te)
更多回答（5 个）
Ismail
2012-11-30
0 个投票
1 个评论
Azzi Abdelmalek
2012-11-30
Ismail I'am not doing all your homework, you have to do some efforts.
Ismail
2012-11-30
0 个投票
2 个评论
Sara Hafeez
2012-11-30
once you know the above its very easy to use it for the other question also.
Sara Hafeez
2012-11-30
you will be using step instead of impulse then.
Md. Anwar Hossain
2019-4-3
0 个投票
Yn{n}=5{x[n]}^2 This equation solve for mat lab work plz help me
类别
在 帮助中心 和 File Exchange 中查找有关 MATLAB 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
