Using Find() in For Loop

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DYLAN
DYLAN 2012-11-30
I am setting up a very simple matlab code to find the first value in each column of a matrix that passes a threshold value. If the matrix has a value that meets the threshold range, then it outputs an index. If the condition is not met, 'NaN' appears.The expected outcome is 1-by-5 matrix that has indice for each column.
However, I could not get IF statement to work. Each line of the code works fine but when it is put together, it does not produce the values I was expecting.
What am I missing here?
xn=[1 0 16 14 18;0 13 4 0 11; 0 4 15 1 52; 0 5 5 17 43; 0 11 5 3 14];
y=[1 24 35 15 16]; %Threshold
t=4*ones(2,5);
SD=1.5;
y_minuse_SD=y-SD*ones(1,5);
y_plus_SD=y+SD*ones(1,5);
d=1:length(xn);
for s=1:5;
if xn(d,s)<y_plus_SD(1,s) & xn(d,s)>=y_minuse_SD(1,s)
t(1,s)=find(xn(d,s)>=y_minuse_SD(1,s),1);
else
t(1,s)=NaN;
end
end

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回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2012-11-30
xn=[1 0 16 14 18;0 13 4 0 11; 0 4 15 1 52; 0 5 5 17 43; 0 11 5 3 14];
y=[1 24 35 15 16]; %Threshold
[n,m]=size(xn);
SD=1.5;
y_m=y-SD;
y_p=y+SD;
z=xn(:);
out=arrayfun(@(x) find(z<y_p(x) & z>y_m(x),1),1:n,'un',0)
out(cellfun(@isempty,out))=num2cell(nan)

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