Switch Case statements MATLAB code in a 'for' loop

6 次查看（过去 30 天）
Tahmid Abdullah
Tahmid Abdullah 2020-6-22
回答： Steven Lord 2020-6-22
I tried running this code below but I am not getting the output as an array of k but instead the otherwise disp'Code not running') is displayed for 4 times. I don't understand where I'm going wrong or is this method wrong? Any help or advise would be appreciated
Code:
L=[6 7 8 9 10];
k=[];
for i=1:length(L)
switch L(i)
case (L(i)<8)
k(i)= -3;
break;
case (L(i)>8)
k(i)=4;
break;
otherwise
disp('Code not running');
end
end
Output:
Code not running
Code not running
Code not running
Code not running
Code not running

请先登录，再回答此问题。

采纳的回答

Steven Lord
Steven Lord 2020-6-22
switch / case isn't the right tool to use here. I suggest using if / elseif / else instead.

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by