Cut part of filename using delimiter

18 次查看（过去 30 天）
Nik Rocky
Nik Rocky 2020-6-24
评论： Nik Rocky 2020-6-24
Hello,
i have files:
001_m1_60_const_20200611_200515_SNR_5_PLL.mat
001_m1_60_const_20200611_200515_SNR_10_PLL.mat
001_m1_60_const_20200611_200515_SNR_15_PLL.mat
001_m1_60_const_20200611_200515_SNR_20_PLL.mat
001_m1_60_const_20200611_200515_SNR_25_PLL.mat
001_m1_60_const_20200611_200515_SNR_30_PLL.mat
The problem is, sometimes is a dataname longer or shorter, for exemple:
008_m3_m4_m1_m2_ramp_const_20200111_200415_SNR_25_PLL.mat
I need to cut "_SNR_30_PLL" and get just a:
001_m1_60_const_20200611_200515.mat
my code is not dynamic, and works just with special name length:
name_sep = split(name,"_");
sep = '_';
name_join=[name_sep{1,1} sep name_sep{2,1} ...... .mat];
so i have to join all pieces, witout last three.
How it is works?
Thank you!

请先登录，再回答此问题。

采纳的回答

Kojiro Saito
Kojiro Saito 2020-6-24
If you're using R2016b or later, extractBefore might be a good option.
newStr = extractBefore(name, "_SNR");
name_join = strcat(newStr, ".mat");

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Characters and Strings 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by