find a row with all elements satisfying a condition

Question

Alon Osovsky 2020-6-24

评论： Alon Osovsky 2020-6-24

I have a matrix that looks something like this:

mat = [20, 3; 43 0; 8 3; 100 3; 3 9];

I want to find the rows of the matrix that all of its elements are satisfying a certain condition. For example, if the condition is:

> 10

The result matrix will be:

[8 3; 3 9];

Because those are the only rows in the matrix that both of their elements are smaller then 10. Is there an easy way to achieve this result? Thanks!

Answer 1

Aakash Mehta 2020-6-24

编辑：Aakash Mehta 2020-6-24

mat = [20, 3; 43 0; 8 3; 100 3; 3 9];

You can use the below code to get rows which satisy the condition.

size1 = size(mat);
vec = zeros(size1(1),1);
for i = 1:size1(1)
    vec(i) = all(mat(i,:)<10);
end

extract those rows in the resultant matrix.

result = mat(vec==1, :);

Alon Osovsky 2020-6-24

I'm searching for a simpler solution (using already existing functions), without a for loop.