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Find a row with all elements satisfying a condition

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Alon Osovsky
Alon Osovsky 2020-6-24
评论： mariajose gomez 2021-7-13
I have a matrix that looks something like this:
mat = [20, 3; 43 0; 8 3; 100 3; 3 9];
I want to find the rows of the matrix that all of its elements are satisfying a certain condition. For example, if the condition is:
> 10
The result matrix will be:
[8 3; 3 9];
Because those are the only rows in the matrix that both of their elements are smaller then 10. Is there an easy way to achieve this result? Thanks!

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采纳的回答

Rasul Khan
Rasul Khan 2020-6-24
You can achieve it with a loop. The required matrix will be stored in res
res = []
for i = 1 : size(mat , 1)
if ~any( mat(i , :) > 10 ) % check for the condition , here if any element is > 10, discard the row
res = [res ; mat(i , :)];
end
end

更多回答（1 个）

darova
darova 2020-6-24
Use logical indexing
mat = [20, 3; 43 0; 8 3; 100 3; 3 9]
ix = sum(mat<10,2)>1;
a1 = mat(ix,:)

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