Replacing Values in Matrix with NaN's based on Row and Column

40 次查看（过去 30 天）
Michelle De Luna
Michelle De Luna 2020-6-24
评论： Michelle De Luna 2020-6-24
Hi everyone!
I hope all of you are well. I'm currently working on replacing specific element values with NaN's within a matrix that is 300x600. I want to replace the values based on pairs of rows and columns that I have previously identified. I'm unsure if I would use a for loop or if I would have to create a mask or if there is a simpler way of approaching the problem, but any help would be greatly appreciated! Thank you in advance! :)
M.

请先登录，再回答此问题。

采纳的回答

madhan ravi
madhan ravi 2020-6-24
编辑：madhan ravi 2020-6-24
matrix(ismember(matrix, [3,7,1])) = nan % an example of replacing numbers 3,7 & 9 with nans
% or
matrix = rand(5); % an example
rows = [2, 5];
columns = [1, 4];
idx = rows + (columns - 1) * size(matrix, 1);
matrix(idx) = nan

更多回答（1 个）

Tommy
Tommy 2020-6-24
Possibly, you could use sub2ind() to convert your rows and columns to linear indices:
ind = sub2ind(size(yourMatrix), yourRows, yourCols);
yourMatrix(ind) = NaN;

类别

在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by