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How to make a structure unique?

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Md. Asadujjaman
Md. Asadujjaman 2020-6-25
评论： Md. Asadujjaman 2020-6-25
emp.x=[];
emp.info=[];
emp.fit=[];
pop=repmat(emp,1,1);
pop(1).x=[1 2 3 4];
pop(2).x=[3 2 1 4];
pop(3).x=[1 2 3 4];
pop(4).x=[2 1 3 4];
How to make the above structure (pop) unique?
The result would be like the following figure.
  4 个评论
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Walter Roberson
Walter Roberson 2020-6-25
X values are not a row vector.
Row vectors are the same length.
Which row vectors are the same length as each other if they are not the X values? (We know they are not the X values because you said that the X values are not row vectors.)
Md. Asadujjaman
Md. Asadujjaman 2020-6-25
sorry, X values are a row vector

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采纳的回答

Rasul Khan
Rasul Khan 2020-6-25
编辑：Rasul Khan 2020-6-25
You can achieve it using this script.
m = [];
for i = 1 : numel(pop)
m = [m ; pop(i).x];
end
[~ , ia , ~] = unique(m , 'rows');
pop = pop(ia);
  2 个评论
Walter Roberson
Walter Roberson 2020-6-25
m = vertcat(pop.x);
[~ , ia , ~] = unique(m , 'rows');
pop = pop(ia);
Md. Asadujjaman
Md. Asadujjaman 2020-6-25
Thank you. It's working.
I got the result.

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