Elements of Array Should not be the Same

2020 6 25
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更新时间：2020 6 28
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Hello,
I have this value for element of my list:
And I have this code:
function [A,B] = CHSHmeasurement(d)
A=zeros(d,d,2,d);
B=A;
projectors_of_sigma_x = [1/sqrt(2)*[1;1],1/sqrt(2)*[1;-1]];
for k = 1:d
for l =1:length(projectors_of_sigma_x)
%A(k,k,1,k)=projectors_of_sigma_x(l);
A(:,:,1,k)=projectors_of_sigma_x(l);
end
end
end
However I have the same element for A although I have the different elements in the projectors_of_sigma_x

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madhan ravi
madhan ravi 2020-6-25
Please provide the full error message. And d?
Gözde Üstün
Gözde Üstün 2020-6-25
编辑：Gözde Üstün 2020-6-25
There is no error message but as you can see I have different value for projectors_of_sigma_x = [1/sqrt(2)*[1;1],1/sqrt(2)*[1;-1]]; (v1 and v2 you can see from the images clearly) but for the A(:,:1,1) and A(:,:,1,2) I have the same matrix and d is = 2

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madhan ravi
madhan ravi 2020-6-25
编辑：madhan ravi 2020-6-25

1 个投票

for k = 1:d
for l =1:d
A(:,:,1,k) = repmat(projectors_of_sigma_x(:,k), 1, d);
end
end
I suggest you to read https://www.mathworks.com/company/newsletters/articles/matrix-indexing-in-matlab.html , first deal with 2D matrices before dealing with higher dimension matrices.

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Gözde Üstün
Gözde Üstün 2020-6-26
Ahh thank you very much I just saw your answer now !
Gözde Üstün
Gözde Üstün 2020-6-27
编辑：Gözde Üstün 2020-6-28
Then we dont need to second for loop right?? or should I change k as l in this line repmat(projectors_of_sigma_x(:,k), 1, d); ?? @madhan ravi
I have a problem for d>2 (and d should be even) For d >2 the result should be block diagonal like that:
0.7071 0.7071 0 0
0.7071 0.7071 0 0
0 0 0.7071 0.7071
0 0 0.7071 0.7071
And I tried almost all combinations with blkdiag but I can't cope with it
for k = 1:d
for l =1:d
A(:,:,1,k) = repmat(projectors_of_sigma_x(:,k), 1, d);
if k > 2
A(:,:,1,k) = repmat({A(:,:,1,k)}, 1, d/2); %This line and the following line I am trying to create a matrix which is a blog diagonal of the previous result for even d and of course d>2
A(:,:,1,k) = blkdiag(A{:,:,1,k});
end
end
end
madhan ravi
madhan ravi 2020-6-28
When do you need ? I don't have time to analyse that sorry :( . I see that you have asked the same question already!
Gözde Üstün
Gözde Üstün 2020-6-28
Ahh no worries! I can wait (till the tuesday) Yeah I asked and each question includes different version of my combination because I have tried too many combiations

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