Skipping certain values in an array but still continuing the array
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I have written a code to skip negative values, but it gives an error, i only want positive values of an array while the negative values must be skipped. (I also dont want zeros in place of these negative values, i just want an array without the negative values)
The code is,
y = zeros(100,1);
for i = 1:100
j = i/10;
y(i,1) = sin(j);
if y(i,1)<0
y(i,1) = [];
end
end
But this gives error
I also tried using the 'break' command, but it gives all zeros just after the first negative value has been encountered.
Can you please suggest a way out?
采纳的回答
madhan ravi
2020-6-28
y = nonzeros(sin(1:1e2));
5 个评论
Sandip Ghatge
2020-6-28
madhan ravi
2020-6-28
y =(sin(1:1e2)<0) .* sin(1:1e2)
Sandip Ghatge
2020-6-28
I think there is a slight typing mistake it must be, (">" in place of "<")
y =(sin(1:1e2)>0) .* sin(1:1e2);
but i am sorry to say that it still does not skip the negative values, but it just replaces the negative values with zeros, and includes these zeros in the array.
Something like this mentioned in an image,
What i am looking for is an array with
0.8415, 0.9093, 0.1411, 0.6570, 0.9894, 0.4121, 0.4202, 0.9906
madhan ravi
2020-6-28
y = nonzeros((sin(1:1e2)>0) .* sin(1:1e2));
Sandip Ghatge
2020-6-28
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