warning Data clipped during write to file
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Im trying to create .wav file
s3 = (s2-min(s2))./(max(s2)-min(s2)).*2-1;
wavwrite(s3, 1250, 16, 'signal.wav');
and I got those warnings:
Warning: Data clipped during write to file:2012-11-23_13-08-18p.wav
> In wavwrite>PCM_Quantize at 285
In wavwrite>write_wavedat at 301
In wavwrite at 138
Does anybody knows how to solve it?
I fougth that clipped during write means that my data are not in the range of -1 and 1?
回答（4 个）
Walter Roberson
2012-12-4
3 个投票
-1 exactly is allowed in the data, but +1 exactly is not allowed.
fatima zahra manzah
2021-4-7
I put this to save the 2 songs
f=44100
audiowrite("singingChurch.wav",singingChurch,f)
audiowrite("singingDungeon1.wav",singingDungeon,f)
i got this :
Warning: Data clipped when writing file.
How can i deal with this please
5 个评论
Walter Roberson
2021-6-18
audiowrite() has these limits:
- uint8: 0 ≤ y ≤ 255
- int16: -32768 ≤ y ≤ +32767
- int32: -2^31 ≤ y ≤ 2^31–1
- single: -1.0 ≤ y ≤ +1.0
- double: -1.0 ≤ y ≤ +1.0
Notice that +1 exactly is permitted for audiowrite() for single() and double(), unlike the earlier wavwrite().
You would have problems if you had double values that were outside +/- 1.0 . For example if you had double data in the range 0 to 255, then audiowrite() would complain and would clip the data. There being a difference between uint8 data in that range and double data in that range.
Shan Shaffi
2021-8-7
Could you tell what needs to be done to bring the values within +/-1.0?
Walter Roberson
2021-8-7
If you are using a newer version of MATLAB, see rescale(); otherwise see mat2gray() .
However, you should be careful about whether you map minimum your data has, to -1, and the maximum to +1, or if you should instead map fixed values to -1 and +1. If you map according to the minimum and maximum present in your data, then you cannot use the result for absolute comparisons.
For example suppose that you were implementing a simple echo. If you had a loud enough original data happening at the time that a loud portion of earlier data was being mixed in, then you could exceed 1.0, and you might consider rescaling according to what is present in the data. For example the input data range might be [-1/2 1/2] and the echo data range might be [-3/4 5/4] and mapping might then be multiplying by 4/5, giving [-3/4 5/4] * 4/5 --> [-3/5 1] as the new data range.
Now suppose you take the same input data range [-1/2 1/2] and apply no echo -- so the output of the echo stage should be exactly the same as the input. Does it make logical sense that the unaltered input needs to be mapped (in which case you would double it to get [-1 1] in this situation)? Or does it make logical sense that instead in such a situation the output should be the same as the input? Remembering that the input expresses relative volumes: does it make sense that a light flute that receives no echo (perhaps the echo was longer than the piece; perhaps the angle was wrong relative to the surroundings) should suddenly become a much louder flute?
Also, watch out: that case of [-3/4 5/4], rescale() and mat2gray() would by default end up processing by subtracting 1/4, getting [-4/4 4/4] rather than scaling by 4/5: you need to decide which approach is right for your purposes.
Shan Shaffi
2021-8-9
Sorry for the late reply. I just read your answer. Thank you for taking the time to answer in detail. This was very helpful. I will try with rescale()
Mohamed
2024-9-10
super hetrodyne reciever, fatima?
Jan
2012-12-5
The documentation explains: For 16 bit precision, the values are limited to –1.0 <= y < +1.0, when the signal is provided as floating point format. A workaround is to convert the data manually before calling wavwrite():
yInt = y * 32768;
yInt(yInt == 32768) = 32767;
5 个评论
Ingo Schalk-Schupp
2015-10-20
However, this does not circumvent clipping but only suppresses the warning. I suggest multiplying by 32767 in the case of 16-bit integers.
Saurabh Kataria
2016-6-8
I agree that it does not prevent clipping, maybe the answer is to normalize the data to fit in [-1,+1] range. Mathematically, I mean:
y = y./(max(abs(y));
Walter Roberson
2016-6-8
+1 exactly is not permitted in wavwrite() . You need to normalize to [-1, 1) if you are going to normalize in floating point.
Rashika Raina
2021-6-17
how to normalize to [-1,1) ?
Walter Roberson
2021-6-18
编辑：Walter Roberson
2021-6-18
I woud recomment using audiowrite(), which does permit +1 exactly.
Judyta
2012-12-5
0 个投票
1 个评论
Daniel Shub
2012-12-5
They are "reduced" by clipping them to the maximum/minimum allowed value. A difference between 1 and 1-2^15 is probably not anything to worry about.
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