Copying std::vector contents to TypedArray
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Is there a better way to copy the contents of a std::vector to a Matlab Array in C++? The following seems long winded.
V is a std::vector in the code below.
matlab::data::ArrayFactory factory;
matlab::data::TypedArray<double> A = factory.createArray<double>({ 1, V.size() });
int i = 0;
for (auto e : V) {
A[i++] = e;
}
采纳的回答
Breno Vincenzo de Almeida
2020-9-20
I managed to do this out after hooours of testing.
matlab::data::ArrayFactory f;
matlab::data::TypedArray<double> A = f.createArray<double>({1, V.size()}, V.data(), V.data()+V.size());
Source: the `matlab::data::ArrayFactory` page in the following link C++ class to create arrays - MATLAB.
But I can't find a way for the ItType method of supplying the data to work.
2 个评论
Jason Laks
2021-2-19
The code above will not compile using the mex command from matlab's command line in R2020a. Does anyone have a code snippet that will work?
Thanks, J.
My attempt at getting the suggestion to work:
matlab::data::ArrayFactory f;
std::vector<double> V(2, 2);
matlab::data::TypedArray<double> A = f.createArray<double>({1,V.size()}, V.data(), V.data()+V.size());
Jason Laks
2021-2-19
Wait... my apologies. The snippet above does compile.
更多回答（1 个）
Paulo Urriza
2023-5-16
编辑：Paulo Urriza
2023-5-16
Type can be deduced automatically if you used the createArray overload for std::iterator.
matlab::data::ArrayFactory f;
auto A = factory.createArray({1, V.size()}, V.begin(), V.end());
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