Detecting samples greater than a threshold and grouping.

Question

Anum Ahmed Pirkani 2020-6-29

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/556537-detecting-samples-greater-than-a-threshold-and-grouping

评论： Anum Ahmed Pirkani 2020-6-29

Hi all,

Lets say we have a vector: A = [1 2 3 5 2 3 5 2 5 3 10 8 9 11 14 1 4 3 3 4 5 3 2 3 4 5 6 4 2 2 3 4 5 6 6 2 2 3 4 11 23 12 56 23 12 34 12 1 3 4 1 2 3 4 5 ];

In the vector, I have applied a threshold of A>5 for detection of any samples greater than 5. So I detect all the bold samples.

However, as a second step, I want to group these samples. As in, first bold set goes to group 1 and second bold set goes to group 2 (All the consecutive samples goes to same group). How can I do it in Matlab in a way that their original indices in vector A are preserved?

Kind Regards

Anum

2 个评论
显示无隐藏无

the cyclist 2020-6-29

What specifically would you want the output to be, for that input vector A? "Goes to a group" is not enough information to design an algorithm.

Anum Ahmed Pirkani 2020-6-29

It can be something like this

Group1val = [10 8 9 11 14]; %group 1 values greater than threshold

Group1ind = [11 12 13 14 15]; %group 1 indices with values greater than threshold

Group2val = [11 23 12 56 23 12 34 12]; %group 2 values greater than threshold

Group2ind = [40 41 42 43 44 45 46 47]; %group 2 indices with values greater than threshold

Indices can be obtained using the find command i.e.

Indices = find(A>5);

But as a next step, I want to seperate them into (in this case) two groups. This is decided if there are 5 values less than the threshold between the groups (in this case there are 24 values less than the threshold between these two groups).

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Image Analyst 2020-6-29

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/556537-detecting-samples-greater-than-a-threshold-and-grouping#answer_458545

在 MATLAB Online 中打开

What you want is bwlabel(), in the Image Processing Toolbox:

A = [1 2 3 5 2 3  5  2 5 3 10 8 9 11 14 1 4 3  3 4 5 3 2 3 4 5 6 4 2 2 3 4 5 6 6  2 2 3 4 11 23 12 56 23 12 34 12 1 3  4  1 2 3 4 5 ]; 
[groups, numGroups] = bwlabel(A > 5)

groups =

Columns 1 through 27

0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 2

Columns 28 through 54

0 0 0 0 0 0 3 3 0 0 0 0 4 4 4 4 4 4 4 4 0 0 0 0 0 0 0

Column 55

0

numGroups =

4