Convert a vector into a matrix (row wise)

62 次查看（过去 30 天）
Amirhossein Moosavi
编辑： Tommy 2020-7-2
Let us assume vector A as follows:
A = [1 2 3 4; 5 6 7 8; 9 10 11 12];
I create two vectors (row wise) from this matrix as follows:
CP = randi([1 numel(A)]-1);
B = transpose(A);
C = B(1:CP);
D = B(CP+1:end);
Now, when I use reshpe function to construct a matrix as the same as A, the result is something else.
reshape([C D], 3, 4)
It seems that I need to make reshape to construct the matrix in row wise. Could you please help me?
  1 个评论
James Tursa
James Tursa 2020-7-2
Can you explain what you want to get as output? I.e., show us the actual numeric output you want.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Tommy
Tommy 2020-7-2
编辑：Tommy 2020-7-2
From the reshape() docs, for the syntax
B = reshape(A,sz)
"The elements in B preserve their columnwise ordering from A."
If you want to "reshape" a vector so that the output matrix is filled along the rows first, you could reverse the requested dimensions in your call to reshape() and then transpose the result:
A2 = reshape([C D], 4, 3)';
I believe this could be generalized to any number of dimensions with a combination of reshape() and permute().

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by