preallocate memory for a struct in a for loop

Question

jason lee 2020-7-2

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/558160-preallocate-memory-for-a-struct-in-a-for-loop

评论： Walter Roberson 2020-7-2

here is my code:

for i = 1:size(filename,1)
    spectra(i).name = filename(i,1:end-4);
    spectra(i).value = readmatrix(filename(i,:));
end
save spectra.mat spectra

MATLAB suggests to preallocate memory for struct spectra.

i am wondering how to do it.

Thank you!

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Answer 1

Walter Roberson 2020-7-2

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https://ww2.mathworks.cn/matlabcentral/answers/558160-preallocate-memory-for-a-struct-in-a-for-loop#answer_459796

在 MATLAB Online 中打开

for i = size(filename,1) : -1 : 1
    spectra(i).name = filename(i,1:end-4);
    spectra(i).value = readmatrix(filename(i,:));
end
save spectra.mat spectra

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jason lee 2020-7-2

yes, it really works!

but why?

could you please make some comments?

Walter Roberson 2020-7-2

在 MATLAB Online 中打开

MATLAB only needs to extend an array dynamically if you write past the existing end of the array. One way to not have to write past the end (triggering a resize) is to write from the end backwards to the beginning: the very first assignment makes it the maximum size, and then you go backwards filling in what was missed.

Note: this will not work exactly like you might expect if the array already exists when you do this. If you for some reason had another for loop around all of this, then the next time through, the number of filenames might be less, and you would probably not want the array left at "the biggest size it has ever been" (though that can be useful sometimes.) One way to deal with this is that after the above loop, you could do

spectra(size(filenamne,1)+1:end) = [];

which would erase any entries past what you used this time.

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