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How can I make a for loop with two diferent indexes

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Nuno
Nuno 2012-12-6
%My problem:
syms w;
for i=1:20
lam=i;
xi = fsolve(@(w) -tan(w/2) + w/2-(4./(lam))*(w/2).^3,[pi()-0.1 3*pi()-0.1]);
X(i) = xi(2)/pi()
end
%This is fine, but now I want to break the intervals in smaller ones:
syms w;
for i=1:0.2:20
lam=i;
xi = fsolve(@(w) -tan(w/2) + w/2-(4./(lam))*(w/2).^3,[pi()-0.1 3*pi()-0.1]);
X(i) = xi(2)/pi()
end
%And I want the values of xi(2)/pi() to be saved in a vector, but it want let me. I understand why, but I can't resolve it.
%Thank you very much to you all.
  2 个评论
Nasser M. Abbasi
Nasser M. Abbasi 2012-12-6
编辑：Nasser M. Abbasi 2012-12-6
You are mixing syms with numerics. Decide what you want to do. Either use numerics or symbolic. Very confusing code. Why calling fsolve() with syms?
But in order to make a symbolic vector, do
range=1:0.2:20;
X = sym(zeros(1, length(range)));
Nuno
Nuno 2012-12-8
Thanks. I forgot to take out the syms part, indeed it isn't necessary.

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采纳的回答

Matt Fig
Matt Fig 2012-12-6
编辑：Matt Fig 2012-12-6
syms w;
cnt = 1:.2:20;
for ii=1:length(cnt)
xi = fsolve(@(w) -tan(w/2) + w/2-4/ii*(w/2).^3,[1 3]*pi-.1);
X(ii) = xi(2)/pi;
end
  4 个评论
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Matt Fig
Matt Fig 2012-12-6
Nuno, did you run the code? It does exactly what you describe. You want to solve the equation for every value of lam in 1:.2:20 and store the second solution in a vector X. That is what the code does....
Nasser, True enough! I just copied Nuno's code and made the minimal changes.

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