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how to find max of a column and run it in a loop

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raqib Iqbal
raqib Iqbal on 3 Jul 2020
Edited: madhan ravi on 3 Jul 2020
device=[1 2 3 4 5 6 7 8 9 10]
block=[1 10;2 11;3 7;4 13;5 14]
new=block(block(:,1) == max(block(:,1)),:)
how to run this max value finding in a loop and display with adding elemnt from device array? like after first find output will be 1 5 14 and last output will be 5 3 7.

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raqib Iqbal
raqib Iqbal on 3 Jul 2020
block=[1 10;2 11;3 7;4 13;5 14] row 3 and min c2 value
raqib Iqbal
raqib Iqbal on 3 Jul 2020
block=[1 10;2 11;3 7;4 13;5 14]
sir you just tell me how to display max of C2 value to min of C2 value (dscending order) with their corresponding c1 value

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madhan ravi
madhan ravi on 3 Jul 2020
Edited: madhan ravi on 3 Jul 2020
C = sortrows(block, 2, 'descend') %?

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