What is my solution?

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eren eren 2012-12-6

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关闭： MATLAB Answer Bot 2021-8-20

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    top2=0;top3=0;
mij=ones(5,5); 
mi=ones(1,5);
X=[242 183 237 141 125;157 181 268 232 220;219 185 151 261 120;331 151 239 203 206;138 213 222 174 189];
Xort=mean(X); %mean for rows
for i=1:5
n(i)=length(X);
end
for i=1:5
    for j=1:5
        top2=top2+(mij(i,j)*(X(i,j)-Xort(i))^2) %top is in english sum. share  %  fraction for v
    end
    top3=top3+(n(i)-1); % denominator of v fraction
end
v=top2/top3;% v is the estimate which i want to calculate
v

İn this program, result is v =3.6694e+003 but it is wrong.in for loop only i=1 and j=1 works correctly. if i=1 j=2, results are bad. Can you help me?

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Thomas 2012-12-6

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What results do you expect?

eren eren 2012-12-6

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i expect around 3500

Sean de Wolski 2012-12-6

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Well 3669.4 isn't that far away. Are you sure it's wrong?

Walter Roberson 2012-12-6

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To check: you are aware that mean(X) is mean(X,1) which is to say mean down the columns? mean(X,2) would be across the rows. Checking to see if you intend rows or columns ?

Image Analyst 2012-12-6

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Can you tell us in words, or can you put in some English comments that say what this does? What is the overall goal of this? What do top2 and top3 and their ratio represent? Maybe there's a simpler way, like using conv2() or something. Also, do you know that length(X) for a 2 D array is the length of the longest dimension (not the number of elements, which is numel(), or the width or height of the array)? I think it's rare to see length() used on a 2D array.

eren eren 2012-12-7