converting multiple file of 4D to 3D files

1 次查看（过去 30 天）
Hanisah noh
Hanisah noh 2020-7-3
评论： Hanisah noh 2020-7-10
i have 80 files of 4D double (140x122x180x#)
i need the files in 3D (140x122x180)
i have tried these solutions but does not come out as expected
files = B % 140x122x180x#
threeD = permute(files[1,2,3,4])
% the result will be 4D double
% i also tried
threeD = squeeze(num2cell(permute(files,[1,2,3,4]),1:3))
% the result will be #x1 cells
current coding :
cd ('path');
files=dir('*.mat'); % find all |.mat| files in the current directory.
totalfile = numel(files); % count those files.
C = cell(1,totalfile); % preallocate a cell array for the loaded data.
for a = 1:totalfile % loop over the number of files.
T = load(files(a).name) % load the data from each file
C(a) = struct2cell(T); % convert structure to cell, allocate to cell array.
M = cat(4,C{:}) % concatenate all MxN matrices into MxNxP array,
% 3 dimensional concatenate
% ???
save(['path/zscore_' num2str(a) '.mat'],'M');
end
thank you
  4 个评论
显示 2更早的评论
Rik
Rik 2020-7-3
I don't know what your variables mean, they're your variables.
The 2 is just an example, as you didn't secribe what value # should have. You wanted a length of 1 in the fourth dimension, that is what this code does. It selects the second book. (in general the first 2 dimensions of an array are called rows and columns, the third is often called page, and some people call the fourth dimension book (i.e. a collection of pages))

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Vinai Datta Thatiparthi
Hey Hanisah,
As mentioned by @Rik, iterate through the collection of 4D matrices to get your 3D values.
For example,
for i = 1:size(B, 4)
A = B(:,:,:,i) % Simple example to slice your 4D matrices
end
Hope this helps!

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 File Operations 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by