How do I define a structure that has an element which is an array?
显示 更早的评论
How do I define a structure that has an element which is an array and for which there are sub elements. I have composed a simple example below of what I want to do along with a failed attempt at the needed assert statements.
function y = payroll(personnel)
%#codegen
% Specify the class of the input as struct.
assert(isstruct(personnel));
% Specify the class and size of the fields r and i
% in the order in which you defined them.
assert(isa(personnel.num_employees,'int32'));
assert(isa(personnel.employee,'int32'));
assert(all(size(personnel.employee) == [5 1]));
assert(isa(personnel.employee(1).salary,'int32'));
for i = personnel.num_employees
total_payroll = total_payroll + personnel.name(i).salary;
end
y = total_payroll;
end
3 个评论
Arnab De
2012-12-7
Do you just want to run the MATLAB code or do you want to generate C code from it?
Wayne Prather
2012-12-7
Sean de Wolski
2012-12-7
Good thread +1
采纳的回答
更多回答(3 个)
John Petersen
2012-12-6
编辑:John Petersen
2012-12-6
1. Find out which assertion fails. The code looks fine.
2. Replace the 'for' loop with
y = sum([personnel.name.salary]);
Jan
2012-12-7
This will crash, if the personnel.employee has more than 2 dimensions:
all(size(personnel.employee) == [5 1])
Better:
isequal(size(personnel.employee), [5 1])
Sean de Wolski
2012-12-7
total_payroll = total_payroll + personnel.name(i).salary;
total_payroll is never defined before being used for the first time!
类别
在 帮助中心 和 File Exchange 中查找有关 Algorithm Design Basics 的更多信息
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!