matlab conersion code needed

Question

raqib Iqbal 2020-7-5

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https://ww2.mathworks.cn/matlabcentral/answers/559688-matlab-conersion-code-needed

评论： Walter Roberson 2020-7-17

clear all;
device = [10:1:20];
block = [1 16;2 18; 3 17; 4 21; 5 23];
block_sort = sortrows(block,-2);
ROM (:,1) = device;
for i =1:length(device)
  if i<=size(block,1)
    ROM (i,2:3) = block_sort(i,:)
  else
    [j,_] = find(block_sort>=device(i)+3)
    ROM (i,2:3) = block_sort(max(j),:)
    
  endif
endfor

#### what i want is this ocatave code output,,,and i want to do it in matlab please run it to see the output.. i need d matlab code of this octave code

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Sindar 2020-7-5

What does the code do? Most people answering questions here are interested in solving Matlab problems, and don't know every other language. If you can tell us what the code does, we can probably build it in Matlab. If you don't understand what the code does, ask an Octave forum

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Answer 1

raqib Iqbal 2020-7-5

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/559688-matlab-conersion-code-needed#answer_461195

WhatsApp Image 2020-07-04 at 4.43.38 PM.jpeg

clear all
 device=10:20
 block=[1 16;2 18;3 17;4 21;5 23]
 ROM = [device(1:size(block,1)).', sortrows(block, 2, 'descend')]

all i want is the from above 10 device 1st 5 device select the column2 max to min value of block matrix and the rest 5 value of device will select min 3 and more difference of value with column 2 .

o/p is like:-->

plz check the attached file for desired output

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Answer 2

Walter Roberson 2020-7-5

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/559688-matlab-conersion-code-needed#answer_461198

Change the endif to end

Change the endfor to end

I did not see anything else at the moment

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raqib Iqbal 2020-7-10

cellular=1:100
resource=[1 8;2 12;3 7;4 18;5 17]
ROM = [cellular(1:size(resource,1)).', sortrows(resource, 2)];
 ROM = ROM(ROM
(:, end) > 5, :)

what changes i have to do,,if i want "cellular value choose the resource column2 value with >5 randomly, and after choosing display will be like :--

1 column:-cellular value column

2nd column:--resource column1

3rd column:--resource 2nd column

Walter Roberson 2020-7-17

Maybe

rc5 = find(resource(:,2) > 5);
rand5 = rc5(randi(length(rc5)));
randresource = resource(rand5, :);
output = [rand5, randresource];

This only creates one output line.... you did not indicate how many output lines need to be created. Also, it is better if you verify that this produces the kind of output that you want before I get into producing a whole table of these things.

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